(2k^2+3k)-(k^2+k-1)=

Solution for (2k^2+3k)-(k^2+k-1)= equation:

Simplifying
(2k2 + 3k) + -1(k2 + k + -1) = 0

Reorder the terms:
(3k + 2k2) + -1(k2 + k + -1) = 0

Remove parenthesis around (3k + 2k2)
3k + 2k2 + -1(k2 + k + -1) = 0

Reorder the terms:
3k + 2k2 + -1(-1 + k + k2) = 0
3k + 2k2 + (-1 * -1 + k * -1 + k2 * -1) = 0
3k + 2k2 + (1 + -1k + -1k2) = 0

Reorder the terms:
1 + 3k + -1k + 2k2 + -1k2 = 0

Combine like terms: 3k + -1k = 2k
1 + 2k + 2k2 + -1k2 = 0

Combine like terms: 2k2 + -1k2 = 1k2
1 + 2k + 1k2 = 0

Solving
1 + 2k + 1k2 = 0

Solving for variable 'k'.

Factor a trinomial.
(1 + k)(1 + k) = 0

Subproblem 1
Set the factor '(1 + k)' equal to zero and attempt to solve:

Simplifying
1 + k = 0

Solving
1 + k = 0

Move all terms containing k to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + k = 0 + -1

Combine like terms: 1 + -1 = 0
0 + k = 0 + -1
k = 0 + -1

Combine like terms: 0 + -1 = -1
k = -1

Simplifying
k = -1
Subproblem 2
Set the factor '(1 + k)' equal to zero and attempt to solve:

Simplifying
1 + k = 0

Solving
1 + k = 0

Move all terms containing k to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + k = 0 + -1

Combine like terms: 1 + -1 = 0
0 + k = 0 + -1
k = 0 + -1

Combine like terms: 0 + -1 = -1
k = -1

Simplifying
k = -1
Solution
k = {-1, -1}